Re: Possible type with bitwise operator (&)

3 Aug 2020

      Em seg., 3 de ago. de 2020 às 12:50, Sjoerd Mullender 
escreveu:
...
On 03/08/2020 15.43, Ranier Vilela wrote:
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Em seg., 3 de ago. de 2020 às 04:02, Sjoerd Mullender
mailto:sjoerd@monetdb.org> escreveu:
Either way is correct.
Are we missing something?
The first form evaluates both (b->ttype != TYPE_void) and b->tkey,
both
    of which result in either 0 or 1.  The single & does a bit-wise AND
on
    those two values and results in 1 if both sides evaluated to 1.
In the second form, if first part evaluates to 0, b->tkey is not
    evaluated,
Sorry, see:
 " In the second form, if first part evaluates to 0, b->tkey is not
evaluated,"
No matter the outcome of the first part, b-> key will always be evaluated.

and if the first part evaluates to 1, the second part is also
...
...
evaluated.  The restult, again, is only 1 if both sides evaluate to
1.
...
Wait, bitwse AND (&) is not shortcut, If first part evaluates to 0
*b->key is stiil evaluated.*
That's correct.  I think I mentioned that.
Sorry, but I think it contradicts your first email, you say "not
evaluated".

regards,
Ranier Vilela