Re: Possible type with bitwise operator (&)

On 03/08/2020 15.43, Ranier Vilela wrote:

Em seg., 3 de ago. de 2020 às 04:02, Sjoerd Mullender mailto:sjoerd@monetdb.org> escreveu:

Either way is correct.

Are we missing something?

The first form evaluates both (b->ttype != TYPE_void) and b->tkey, both of which result in either 0 or 1.  The single & does a bit-wise AND on those two values and results in 1 if both sides evaluated to 1.

In the second form, if first part evaluates to 0, b->tkey is not evaluated, and if the first part evaluates to 1, the second part is also evaluated.  The restult, again, is only 1 if both sides evaluate to 1.

Wait, bitwse AND (&) is not shortcut, If first part evaluates to 0 *b->key is stiil evaluated.*

That's correct. I think I mentioned that.

It is never good to mix relational operators with bitwise operators.

I don't agree with this statement in its generality.

regards, Ranier Vilela

_______________________________________________ developers-list mailing list developers-list@monetdb.org https://www.monetdb.org/mailman/listinfo/developers-list

-- Sjoerd Mullender