Re: SUM() OVER (ORDER BY..)

29 Apr 2016


      Ignore that, my bad. You can also aggregate over all rows, of course.


On 29 April 2016 at 09:37, Roberto Cornacchia 
wrote:
...
I think what you are looking for is SUM(..) OVER(PARTITION BY ..)
Otherwise where would the groups for the sum come from?
Roberto
On 29 April 2016 at 09:28, Anthony Damico  wrote:
...
hi, monetdb does not support SUM() OVER commands..  does anyone have a
smart alternative to implement this?  thanks
SELECT
        batch_id,
        job_count,
        SUM(job_count) OVER (ORDER BY duration) as cumjobs,
        SUM(job_count) over () as totjobs,
        duration
    FROM
        test_data ;
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