20 Apr
2008
20 Apr
'08
12:43 p.m.
this should be the same: table columns: col1..col16 : smallint null col17..col160: real null select col1, col2, sum(col17), sum(col18), sum(col19) from thetable group by col1, col2; should return a total of about 8000 rows, each row would be an aggregation from about 50,000 rows from "thetable". -- View this message in context: http://www.nabble.com/mserver5-process-locked-unkillable-tp16789362p16790887... Sent from the monetdb-users mailing list archive at Nabble.com.