Re: [MonetDB-users] Get attribute value as text how?

Hello Roy, I don't understand your question. Could you please elaborate? Wouter 2009/8/5 Roy Walter :

Thanks Wouter, very helpful. This works fine in my application:

  <p>{xs:string(exactly-one($res/../@speakername))}: {$res}</p>

Another quick question if I may: how should I encode an entity as in the following example so that it works in the context of a query:

  <h4>Keynote — {$res/../preceding-sibling::heading[1]/text()}</h4>

-- Roy

Wouter Alink wrote:

...

Hello Roy,

One of the things about MonetDB/XQuery that it does static typing.

So the compiler tries to figure out the cardinality of "$res/../@speakername" and cannot know whether it happens 0 or more times, and will therefore not be able to detect whether there is exactly one speakername attribute matching this query.

Because xs:string will need exactly 1 argument, you need to either give a hint that there will be exactly one attribute, or otherwise pass each speakername attribute to the function.

So either:  <p>{xs:string(exactly-one($res/../@speakername))}: {$res}</p> or:  <p>{for $i in $res/../@speakername return xs:string($i)}: {$res}</p>

should work. If not, please give us some insight in the error which was returned.

Hope this helps, Wouter

2009/8/5 Roy Walter :

...

The following XQuery fragment will add the speakername attribute as an attribute of the <p> tag:

  <p>{$res/../@speakername}: {$res}</p>

becomes:

  <p speakername="Roy Walter">Some text...</p>

What I want is:

  <p>Roy Walter: Some text...</p>

How does MonetDB/XQuery handle this? I tried:

  <p>{xs:string($res/../@speakername)}: {$res}</p>

but it errors.

-- Roy

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